Friday, February 26, 2010
State plane plot for forward converter problem
If I understand this correctly, in the case of the forward converter the state plane diagram will look a lot like the very initial problem we did in class (the one with the current src in parallel with the capacitor) except because of -ve sign on nVg which I took as Vbase, it'll be in the second quadrant.
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2 comments:
hello Yusuf
I think you are right. The centre of the circle will be (-1,JF), where JF=IF/Ibase.
... or the fourth quadrant depending on your Vbase sign convention.
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