Monday, March 8, 2010
F=1, J=2 case
Can someone please describe the state plane in this case. The way I get it does not make complete sense to me becausein this case MA1 = pi, MA2 = pi-2, alpha=beta=pi/2 and two of the centers are at 0,0 one at 2,0 and one at -2,0. So basically the Q2 subinterval does not start where the D1 subinterval ends. This is what I a cannot understand. Any hints?
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2 comments:
Yusuf,
I calculated beta = pi and alpha = 0. That way, the solution is a pure circle centered at the origin with radius equal to pi. I think what is happening is that the current and voltage waveforms align with each other (so the tank has no effect as far as leading and lagging is concerned). So only the Q's are conducting.
Brandon
Yusuf, My take is: b/c the fs = fo (F=1) the tank appears purely resistive for the transition. So the V-I (j-M) relationship is linear and you will have a straight line trajectory at those transitions....I think.
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