Sunday, February 5, 2012
HW #2 19.1 E and G
I am having a little trouble figuring out the peak current through the transistor for 19.1 Part E. So far my thoughts are that the peak transistor current will match the peak ig, input current, which is also the same as the peak current value through Cb. So I get something like Ig = Is1cos(phi_s)/pi and want to solve for Is1. I feel like I should relate the equation back to power, i.e. Pg = VgIg = <ps(t)>, but I don't know how to solve for the input power either without Ig. I've been circling around this for a little while, and feel like I missing some minor(?) detail. Any help is appreciated. Thanks!
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2 comments:
Hi Carissa,
I think your goal is correct: solve for Is1. Another way to find Is1 is to solve Vs1/||Z_in(s)||, substituting f for the f_s found in parts (d) & (f). Hope that helps.
Thanks Keith,
I tried that the first time around and calculated a completely rediculous value for Is1. Turned out to be a math error rather then conceptual. Hate it when that happens :)
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